Решение задачи Array 8

#include <stdio.h>
 
int main(void)
{
    int a[10];
    int n, i,k=0;
 
    printf("N: ");
    scanf("%i",&n);
    for (i=0; i<n; ++i){
        printf("a[%i] : ",i);
        scanf("%i",&a[i]);
    }
 
    for (i=0; i<n; ++i)
        if (a[i]%2 != 0){
            printf("%i\n",a[i]);
            ++k;
        }
    printf("%i\n",k);
    return 0;
}

import random
import math

N = random.randrange(1,10)
A = [random.randrange(1,21) for i in range(N)]
print("N = ", N)
print(A)
K = 0
for i in range(N):
    if A[i]%2 == 1:
        K += 1
        print(i,":",A[i],end='; ')
print()
print('Amount of odd numbers = ', K)
									

program Array8;
var
  a:array[1..10] of integer;
  N,i,K:Integer;
 
begin
  Write('N:');
  Readln(N);
  for i:=1 to N do
   begin
    write(i,' :');
    readln(a[i]);
   end;
 
  K:=0;
  for i:=1 to N do
    if i mod 2 <> 0 then
     begin
      writeln(i,' : ',a[i]);
      inc(k);
     end;
  Writeln('K:',K);
end.