Решение задачи Array 50

#include <stdio.h>
int main(void)
{
    int a[10];
    int n;
 
    printf("N: ");
    scanf("%i",&n);
 
    int i;
    for (i=0; i<n; ++i){
        printf("a[%i] : ",i+1);
        scanf("%i",&a[i]);
    }
 
    int num=0,i2;
    for (i=0; i<n-1;++i){
        for (i2=i+1; i2<n;++i2){             if (a[i]>a[i2]){
                num++;
            }
        }
    }
    printf("%i \n",num);
 
    return 0;
}

import random

N = random.randrange(2,4)
a = [i+1 for i in range(N)]
random.shuffle(a)

print("N:",N)
print("Array:",a)

n_inverse = 0
for i in range(0,N-1) :
    for j in range(i+1,N) :
        if a[i] > a[j] :
            n_inverse += 1

print("Number of Inverse:", n_inverse)
									

program Array50;
var
  a:array[1..10] of integer;
  N,i,i2, Num:Integer;
  check: Boolean;
 
 
begin
  Write('N: ');
  Readln(N);
 
  for i:=1 to N do
   begin
    write(i,' :');
    readln(a[i]);
   end;
  Num:=0;
  for i:=1 to N-1 do
    for i2:=i+1 to N do
     if a[i]>a[i2] then inc(Num);
 
  Writeln(Num);
end.