Решение задачи Array 53

#include <stdio.h>
int main(void)
{
    float a[10],b[10],c[10];
    int n;
 
    printf("N: ");
    scanf("%i",&n);
 
    int k;
    for (k=0; k<n; ++k){
        printf("a[%i] : ",k+1);
        scanf("%f",&a[k]);
    }
 
    for (k=0; k<n; ++k){
        printf("b[%i] : ",k+1);
        scanf("%f",&b[k]);
    }
 
    for (k=0; k<n;++k){
        if (a[k]>b[k]) c[k]=a[k];
        else c[k]=b[k];
    }
 
    printf("C: \n");
    for (k=0; k<n; ++k) printf("  %i: %f\n",k+1,c[k]);
 
    return 0;
}

import random

N = random.randrange(2,11)
a = [random.randrange(1,11) for i in range(N)]
b = [random.randrange(1,11) for i in range(N)]
c = []

print("N:",N)
print("Array a:\n",a)
print("Array b:\n",b)

for i in range(0,N) :
    c.append(a[i] if a[i] > b[i] else b[i])

print("Array c:\n",c)
									

program Array53;
var
  a,b,c:array[1..10] of real;
  N,k:Integer;
 
 
begin
  Write('N: ');
  Readln(N);
 
  Writeln('A: ');
  for k:=1 to N do
   begin
    write(k,' :');
    readln(a[k]);
   end;
 
  Writeln('B: ');
  for k:=1 to N do
   begin
    write(k,' :');
    readln(b[k]);
   end;
 
  for k:=1 to N do
      if a[k]<b[k] then c[k]:=b[k]
      else c[k]:=a[k];
 
  Writeln('C: ');
  for k:=1 to N do writeln(k,' :',c[k]);
end.