Решение задачи Array 3

#include <stdio.h>
 
int main(void)
{
    int a[10];
    int d,n, i;
 
    printf("N: ");
    scanf("%i",&n);
 
    printf("A[o]: ");
    scanf("%i",&a[0]);
 
    printf("D: ");
    scanf("%i",&d);
 
    for (i=1; i<n; ++i) a[i]=a[0]+(i)*d;
 
    for (i=0; i<n; ++i) printf("%i : %i\n",i,a[i]);
    return 0;
}

import random

N = random.randrange(1,10)
A = random.randrange(-10,10)
D = round(random.uniform(-5,5),1)
print("N = ", N)
print("A = ", A)
print("D = ", D)

a1 = []
for i in range(N):
    x = A + i*D
    a1.append(x)
print(a1)

a2 = [A + i*D for i in range(N)]
print(a2)
									

program Array3;
var
  a:array[1..10] of integer;
  D,N,i:Integer;
 
begin
  Write('N:');
  Readln(N);
  Write('A_1:');
  Readln(a[1]);
  Write('D:');
  Readln(D);
  for i:=2 to N do a[i]:=a[1]+(i-1)*D;
 
  for i:=1 to N do writeln(i,' : ',a[i]);
end.