Решение задачи Proc 57

#include <bits/stdc++.h>

using namespace std;
double func(double x1, double y1, double x2, double y2, double x3, double y3)
{
    double a = sqrt(pow((x1 - x2),2) + pow((y1 - y2),2));
    double b = sqrt(pow((x1 - x3),2) + pow((y1 - y3),2));
    double c = sqrt(pow((x2 - x3),2) + pow((y2 - y3),2));
    return a + b + c;
}
int main()
{
    double x1, y1, x2, y2, x3, y3, x4, y4;
    cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3 >> x4 >> y4;
    cout << func(x1, y1, x2, y2, x3, y3) << endl;
    cout << func(x1, y1, x2, y2, x4, y4) << endl;
    cout << func(x1, y1, x3, y3, x4, y4) << endl;
    return 0;
}

import math
import numpy as np
import random

def Leng(xA, yA, xB, yB):
    d = math.sqrt((xA - xB)**2 + (yA - yB)**2)
    return d

def Perim(xA, yA, xB, yB, xC, yC):
    d_AB = Leng(xA, yA, xB, yB)
    d_AC = Leng(xA, yA, xC, yC)
    d_BC = Leng(xB, yB, xC, yC)
    return d_AB + d_AC + d_BC


x1,x2,x3,y1,y2,y3 = list(np.random.choice(range(-10, 11), 6))
#x1,x2,x3,y1,y2,y3 = [0,3,0,0,0,4]
while (x3-x1)*(y2-y1) == (y3-y1)*(x2-x1):
    x1,x2,x3,y1,y2,y3 = list(np.random.choice(range(-10, 11), 6))    
x4, y4 = random.sample(range(-10, 11), 2)

A_x = x1
A_y = y1
B_x = x2
B_y = y2
C_x = x3
C_y = y3
D_x = x4
D_y = y4

A_x = 0
A_y = 0
B_x = 0
B_y = 3
C_x = 4
C_y = 0

print("Вершина A (x, y): ({0},{1})".format(A_x, A_y))
print("Вершина B (x, y): ({0},{1})".format(B_x, B_y))

 

print("Вершина C (x, y): ({0},{1})".format(C_x, C_y))
print("Вершина D (x, y): ({0},{1})".format(D_x, D_y))

p = Perim(A_x, A_y, B_x, B_y, C_x, C_y)
print("Периметр треугольника ABC: ", p)

p = Perim(A_x, A_y, B_x, B_y, D_x, D_y)
print("Периметр треугольника ABD: ", p)

p = Perim(A_x, A_y, C_x, C_y, D_x, D_y)
print("Периметр треугольника ABC: ", p)