Решение задачи String 26

#include <bits/stdc++.h>

using namespace std;

int main()
{
    int n;
    string s;
    cin >> n >> s;
    if(s.size() > n)
        s.erase(0, s.size() - n);
    else
        s.insert(s.end(), n - s.size(), '.');
    cout << s << endl;
    return 0;
}

# -*- coding: utf-8 -*-
import random

ru_letters = u"абвгдежзийклмнопрстуфхцчшщъыьэюяАБВГДЕЖЗИЙКЛМНОПРСТУФХЦЧШЩЪЫЬЭЮЯ"
en_letters = u"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
tj_letters = u"ғӣқӯҳҷҒӢҚӮҲҶ"
digits = u"0123456789"

letters = ru_letters + en_letters + tj_letters + digits

N = random.randrange(1,21)
K = random.randrange(1,21)
S = ''.join(random.choice(letters) for _ in range(K))
print("N:",N)
print("K:",K)
print("S:",S)

S_length = len(S)
print("Length of S:",S_length)

if S_length > N:
    x = S_length - N
    S_new = S[x:]
    #print(x,":",S[x:])
else:
    x = N - S_length
    S_new = '.'*x + S
    #print(x,":",'.'*x,":",S)
print("\nNew S:",S_new)
print("Length of new S:",len(S_new))
									

program String26;
var
 N,i:integer;
 S:string;
 
begin
 Write('N:');
 Readln(N);
 Write('S:');
 Readln(S);
 
 if length(S)>N then  delete(S,1,length(S)-N)
 else if length(S)<N then  for i:=length(S) to N-1 do s:=s+'.';
 
 writeln(S);
end.