Решение задачи Minmax 29

#include <stdio.h>
int main(void)
{
    int n,i,ni,nmin,num=0,maxnum=0;
    printf("N:");
    scanf("%i", &n);
    for (i=1; i<=n; ++i){
        printf("%i>",i);
        scanf("%i", &ni);
        if((i==1)||(ni<nmin)) {
            nmin=ni;
            num=0;
            maxnum=0;
        }
        if (ni==nmin) ++num;
        else {
            if (num>maxnum) maxnum=num;
            num=0;
        }
    }
    if ((num>maxnum)&&(ni==nmin)) maxnum=num;
 
    printf("%i\n",maxnum);
    return 0;
}

import random

N = random.randrange(2,20)
print("N = ",N)

x_prev = random.randint(0,4)
x_min = x_prev
print(x_prev,end="; ");
largest = 1
temp_largest = 1
for i in range(1,N):
    x = random.randint(0,4)
    print(x,end="; ");
    if x == x_prev:
        temp_largest += 1
    else:
        if x_prev < x_min:
            largest = temp_largest
            x_min = x_prev
        elif x_prev == x_min and temp_largest > largest:
            largest = temp_largest
        temp_largest = 1
    x_prev = x
if x < x_min:
    largest = temp_largest
    x_min = x_prev
elif x == x_min and temp_largest > largest:
    largest = temp_largest

print()
print("Minimum:",x_min)
print("Length of Largest Series of Min:",largest)
									

program Minmax29;
 
var
  N,i,Ni,Nmin,Num,MaxNum:Integer;
 
begin
 
  Num:=0;
  MaxNum:=0;
  Write('N:');
  Readln(N);
  for i:=1 to N do
   begin
     Write(i,' число:');
     Readln(Ni);
     if (i=1) or (Ni<Nmin) then
      begin
       Nmin:=Ni;
       Num:=0;
       MaxNum:=0;
      end;
 
 
     if Ni=Nmin then inc(Num)
     else
      begin
       if Num>MaxNum then MaxNum:=Num;
       Num:=0;
      end;
 
   end;
   if (Num>MaxNum) and (ni=Nmin) then MaxNum:=Num;
 
   Writeln(MaxNum);
end.